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An absolute-value equation solved by cases keeps only the roots inside each case

algebra · absolute-value, equation, case-analysis

Idea

y = |x − 1| with both branches extended as dashed lines; y = 2x meets the V at x = 1/3 and the dashed extension at x = −1

Splitting $|x - c|$ into cases swaps the V for one straight branch at a time, but each case equation solves against that branch's whole line, not just its half. A root on the wrong half is where the other curve meets the dashed extension, not the graph, and it has to be thrown out.

Definition

To solve an equation containing $|x - c|$:

The solution set is the union of what the two cases keep.

Example

$|x - 1| = 2x$. Case $x \ge 1$: $x - 1 = 2x$ gives $x = -1$, which is not $\ge 1$, so it is rejected. Case $x < 1$: $1 - x = 2x$ gives $x = \tfrac13$, kept. One solution, $x = \tfrac13$.

Pitfalls

Test each root against its own case, not the other one. A root rejected in one case is not a solution at all — it does not move over to the other case.

See also

Two functions are equal when they agree at every point of their domain